Express answer in exact form.
Find the area of one segment formed by a square with sides of 6" inscribed in a circle.
(Hint: use the ratio of 1:1:√2 to find the radius of the circle.)

here what my teacher said ------------Since we know that the diagonals of a square are perpendicular, the triangle that is pictured must be a 45º – 45º – 90º right triangle. Since the sides of a 45º – 45º – 90º triangle are in the ratio of 1 – 1 – sqrt(2) , and the hypotenuse has length 6 inches, the two legs of the triangle (and the radius of the circle) must have length inches. r = (1/sqrt(2) * 6 inches = 3

Question

Express answer in exact form.
Find the area of one segment formed by a square with sides of 6"	 inscribed in a circle.
(Hint: use the ratio of 1:1:√2 to find the radius of the circle.)

here what my teacher said ------------>Since we know that the diagonals of a square are perpendicular, the triangle that is pictured must be a 45º – 45º – 90º right triangle. Since the sides of a 45º – 45º – 90º triangle are in the ratio of 1 – 1 – sqrt(2) , and the hypotenuse has length 6 inches, the two legs of the triangle (and the radius of the circle) must have length inches. r = (1/sqrt(2) * 6 inches = 3