Question

evaluate
log 16, given that log 2=0.4307
u u
how is this done?

Answer 1

Little bit long but try this way-
Let log u (16)=x
Then 16=u^x
2^4=u^x
so,
2=u^(x/4)
Now log (u) 2=0.4307 gives
2=u^0.4307
so u^(x/4)=u^0.4307
so x/4=0.4307
x=1.7228

Answer 2

16 = 2^4-> 4 log 2...

Answer 3

Hence the required value of the logarithm is 1.7228

Answer 4

thank you....i understood

Answer 5

Good, kinda messy though!

Answer 6

Oh, I see the u's are part of the question...duh.

They are just floating alone in my browser.

Answer 7

\[\log_u(16)=\log_u(2^4)=4\log_u(2)=4[0.4307]=1.7228\]

Answer 8

So I was right, it's a one liner...

Answer 9

lol