Question

Find the volume of the solid obtained by rotating the region bounded by y = x and y = x^2 about the line x = -2.

Answer 1

Those are the choices I was given as a result..
(5/6)pi
(14/3)pi
(Pi/6)
(11/3)Pi

Answer 2

\[\frac{5\pi}{6}\]

Answer 3

\[2\pi\int\limits_{0}^{1}(x+2)(x-x^2)dx\]

Answer 4

Ahhhhhhhhh...I knew I was forgetting something. calc 2 was so long ago :(

Answer 5

you were close...just needed to make the radius bigger

Answer 6

I knew I had to do something with that -2 >.> lol

Answer 7

could have also done washers

\[π\cdot\int\limits_{0}^{1}[(\sqrt{y}+2)^{2}-(y+2)^2]dy=\frac{5\pi}{6}\]