After a certain drug is injected into a patient, the concentration c of the drug in the bloodstream is monitored. At time t ≥ 0 (in minutes since the injection), the concentration (in mg/L) is given by
c(t) =(40t)/(t^2 + 2)

What eventually happens to the concentration of drug in the bloodstream?

Question

After a certain drug is injected into a patient, the concentration c of the drug in the bloodstream is monitored. At time t ≥ 0 (in minutes since the injection), the concentration (in mg/L) is given by
c(t) =(40t)/(t^2 + 2)

What eventually happens to the concentration of drug in the bloodstream?

anonymous · Answer

it deceases to 0

anonymous · Answer

since degree of the denominator (2) is bigger than degree of the numerator (1)
$$\lim_{t\rightarrow \infty} c(t)=0$$

anonymous · Answer

would that be the same as a $$-\infty$$

anonymous · Answer

ooooooooooooooooh no

anonymous · Answer

0 is 0 not 
$$-\infty$$

anonymous · Answer

ok just making sure because i knew your answer made sense i had just never had a problem like that with an answer 0

anonymous · Answer

doesn't make any sense in this case anyway. you cannot have a negative amount of a drug in your blood, let alone - infinity amount!

anonymous · Answer

yeah lol i just usually had the option between $$-\infty or \infty$$

anonymous · Answer

so i just wanted to make sure