Question

Solve the equation. (Enter all answers including repetitions. If there is no solution, enter NO SOLUTION.)
sqrt 20-x + sqrt20+x=8
x= (smaller value)
x= (larger value)

Answer 1

i suppose you mean
\[\sqrt{20-x}+\sqrt{20+x}=8\]

Answer 2

is that right?
its not really what you have written but sometimes i have esp

Answer 3

yes!

Answer 4

ok subtract want those square root thingys on both sides
and then square
and then you will have to get another square rooty by itself
and then square to get rid of that one

Answer 5

\[\sqrt{20-x}=8-\sqrt{20+x}\]
\[(\sqrt{20-x)}^2=(8-\sqrt{20+x})^2\]
\[20-x=8^2-2*8*\sqrt{20+x}+(20+x)\]

Answer 6

let me know if if you still are having trouble with this

Answer 7

I just multiply?

Answer 8

\[20-x=64-16\sqrt{20+x}+20+x\]

Answer 9

move everything over except the square root thingy

Answer 10

if you want to leave the 16 with it you can

Answer 11

\[20-20-x+x-64=-16\sqrt{20+x}\]
\[-64=-16\sqrt{20+x}\]
\[64=16\sqrt{20+x}\]
\[\frac{64}{16}=\frac{16\sqrt{20+x}}{16}\]
\[4=\sqrt{20+x}\]

Answer 12

;S

Answer 13

whats that mean

Answer 14

i see a small error

Answer 15

uh oh

Answer 16

with your x's

Answer 17

they don't cancel

Answer 18

i see it too

Answer 19

i subtracted it on one sides and added it on the other lol

Answer 20

\[-64-2x=-16\sqrt{20+x}\]

Answer 21

You shouldn't be doing this stuff this late at night...not good for the brain ;)

Answer 22

lol

Answer 23

\[-(64+2x)=-16\sqrt{20+x}\]
\[64+2x=16\sqrt{20+x}\]

Answer 24

\[(64+2x)^2=(16\sqrt{20+x})^2\]
\[64^2+2*64*2x+(2x)^2=16(20+x)\]
\[4096+256x+4x^2=320+16x\]
\[4x^2+256x-16x+4096-320=0\]
\[4x^2+240x+3776=0\]
please let me know if made anymore mistakes

Answer 25

you can divide both sides by 4

Answer 26

then you might want to try factoring or you can use the quad formula

Answer 27

check your solutions
you may get one that does not work

Answer 28

or both

Answer 29

you missed the \[16^2\] on the rhs

Answer 30

no!!!!!!!!!!

Answer 31

i cant do it anymore

Answer 32

lol

Answer 33

deep breath!
\[64^2+2*64*2x+(2x)^2=16^2(20+x)\]

Answer 34

lol

Answer 35

\[4096+256x+4x^2=256(20+x)\]
\[4096+256x+4x^2=5120+256x\]
\[4x^2+256x-256x=5120-4096\]

Answer 36

\[4x^2=1024\]

Answer 37

this is easy to solve then the wrong equation i gave you earlier lol

Answer 38

nice

Answer 39

please tell me you can finish this ep4710
thanks for your help zarkon

Answer 40

you deserve another medal for all that work

Answer 41

omg i suck

Answer 42

too many errors

Answer 43

na

Answer 44

it's all good

Answer 45

you know your students are learning if they are making corrections to your work
i just hope people notice them not you zarkon because you know everything
but yeah he probably wouldn't have caught them