Question

Simplify the Complex Fraction
1 over x-1 - 1 over x+1
Over 1 x^2-1

Answer 1

\[[1/ (x-2)] \over [(x-1)/(x ^{2}-1)]\]

is that the correct fraction?

Answer 2

If so, you would use the "same change flip" method and multiply by the recipricol of the denominator\[1/ (x-2) * (x ^{2}-1)/ (x-1)\] if you factor x^2-1 into (x+1)(x-1) you can cancel the (x-1) in the denominator with the one in the numerator. the final fraction you should end up with would then be \[(x+1) \over (x-2)\]