Question

15.) "where defined, find cos(theta) - sin(theta). simplify your answer."

Answer 1

\[\cos(\Theta) - \sin(\Theta)\]

Answer 2

that is one fat
\[\theta\]

Answer 3

what does it mean "find
\[\sin(\theta)-\cos(\theta)\]?

Answer 4

you want some other expression for this?

Answer 5

i hav no clue

Answer 6

i suppose so? that's all the instruction i got.

Answer 7

oh oh oh i think i have seen these before. hold on

Answer 8

you are supposed to write as a single trig function. i did one of these recently

Answer 9

can you tell me the name of the topic?

Answer 10

i had a nice recourse for these that made it easy. but i cannot find it. if you just want the answer it is here
http://www.wolframalpha.com/input/?i=sin(x)+-+cos(x)

Answer 11

but i had a nice explanation and method for getting these. i just cannot find it

Answer 12

trigonometry?

Answer 13

yeah i got that part. are you using a book? what is the section called?

Answer 14

It's a placement practice test :)

Answer 15

I got it off of some community college website.

Answer 16

the question isnt clear to me.. when it says 'where defined' .. .. .. i dont see why is cant be straightforward and ask for a derivative or something

Answer 17

what it is asking for is to write this as a single trig function. if it actually does not say that then it is a dumb question. did you see the answer i sent?

Answer 18

it is of course always defined

Answer 19

on the answer sheet. it says the answer is \[\cot(\theta) \cos(\theta)\]

Answer 20

no. ALL IT SAYS is "where defined, find cos(theta)-sin(theta). simplify your answer"

Answer 21

what???

Answer 22

-_- that's why im confused.

Answer 23

no no no
that is not right.

Answer 24

cause .. for me... they do not equal each other

Answer 25

no they do not so forget about it . one answer is
\[\sqrt{2}\sin(\theta-\frac{\pi}{4})\]

Answer 26

i am trying to find the nice paper i had that showed how to do this, but i cannot. the answer you wrote is just straight up wrong so ignore it

Answer 27

LoL :)

Answer 28

thanks :)

Answer 29

I guess there are a few things u might do if u want to get a different expression.

U could use Sin/Cos = Tan

Or square it -< sin^2 + cos^2 -2sin cos -> 1- 2 sin cos