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Mathematics 18 Online
OpenStudy (anonymous):

exponent rules?

OpenStudy (anonymous):

yes, exponents rule

OpenStudy (anonymous):

\[[5^(x-1) \times 5^(3x) ]/5^(4x+1)\]

OpenStudy (anonymous):

succinctly put here http://mathworld.wolfram.com/ExponentLaws.html

OpenStudy (anonymous):

LOL :)

OpenStudy (angela210793):

(x^a)^b=x^(ab) x^a*x^b=x^(a+b) x^a/x^b=x^(a-b) x^-a=1/x^a)

OpenStudy (anonymous):

\[\frac{5^{x-1} \times 5^{3x} }{5^{4x+1}}\]

OpenStudy (anonymous):

is that it?

OpenStudy (anonymous):

yes :)

OpenStudy (anonymous):

ok base is same so add exponents in numerator and subtract the one in the denominator all the work is there

OpenStudy (anonymous):

\[x-1+3x=4x-1\] \[4x-1-(4x+1)=4x-1-4x-1=-2\]

OpenStudy (anonymous):

and so your answer is \[5^{-2}=\frac{1}{5^2}=\frac{1}{25}\]

OpenStudy (anonymous):

hope steps are clear

OpenStudy (anonymous):

thank you!!

OpenStudy (anonymous):

yw

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