Question

∫_2^3▒(9x-2x^3 )dx evaluate

Answer 1

lolwut?

Answer 2

\[∫_2^3(9x-2x^3 )dx\]

Answer 3

ahh

Answer 4

answer = -10

Answer 5

[9/2x^2 - 2/2*x^4] 3_0= -40.5

Answer 6

um... can u explain?

Answer 7

ishaan can you work this out

Answer 8

you can integrate by separating integrals

\[\int\limits_{2}^{3} 9x dx - \int\limits_{2}^{3}2x ^{3}dx\]

Answer 9

ah yes

Answer 10

ok here we go av

Answer 11

\[\int_2^3 9xdx - 2x^3dx\]
\[\frac{9x^2}{2} - \frac{2x^4}{4} |_2^3\]

Answer 12

then:
\[\int\limits_{2}^{3} 9x = 45/2\]
\[\int\limits_{2}^{3}-2x ^{3}dx = -65/2\]

45/2 - 65/2 = -10

Answer 13

oh sorry it was 3_2 i thought it was 3_0

Answer 14

ah sorry there should be no = it happened by mistake

Answer 15

av do you understand that

Answer 16

ah typo let me write it again

Answer 17

what did you mean by that?

Answer 18

sorry I didnt realize that

Answer 19

\[\frac{81}{2} - \frac{2 \times 81}{4} - \frac{9 \times 4}{2} + \frac{2 \times 16}{4}\]

Answer 20

This will give you

-18 + 8 =-10

Answer 21

Diego go the Same too Medals for Diego

Answer 22

Diogo. its portuguese, not spanish hehe. Thanks

Answer 23

Oh sorry Diogo