whats is the GCF OF 2X^2-4X2?
the x part looks simple enough, they both have an x^2 in common right?
YEA
a simple way to determine this is to simply write out the factors of each one and compare 4x^2 factors to: 1,2,4, x,x 2x^2 factors to: 1,2 x,x what is the biggest factor they have in common?
2
great :) than thats our answer; 2 and those xx parts are common to them all 2x^2
ok thanks i got another one
the process is the same regardless of the numbers :) so whatcha got?
8x^9y^6+4x^7y^5-16x^4y^3?
dag nab ask your math teacher what is the greatest common factor of 365 !
if you want a "greatest common factor" you have to have separate terms. i know what the problem wants. it wants the greatest common factor of each term, but the question makes no sense as asked
lets split our terms up and factor them out 8 x^9 y^6 : 1,2,4,8 x,x,x,x,x,x,x,x y,y,y,y,y,y 4 x^7 y^5 1,2,4 x,x,x,x,x,x,x y,y,y,y,y 16 x^4 y^3 1,2,4,8,16 x,x,x,x y,y,y now we determine what it is the all have in common
8
colse; but 4 doesnt have an 8 as a factor; look again please
the greatest common factor of \[8x^9y^6, 4x^7y^5,16x^4y^3\] is \[4x^4y^3\] because that is a factor that each term has in common
4
no wonder students are confused.
4 is good; that is the number part; how many xs do they have in common ?
hint: its always gonna be the smallest amount that you see
8 x^9 y^6 : 1,2,4,8 x,x,x,x,x,x,x,x y,y,y,y,y,y 4 x^7 y^5 1,2,4 x,x,x,x,x,x,x y,y,y,y,y 16 x^4 y^3 1,2,4,8,16 \(\underbrace {x,x,x,x}\) \(\underbrace{y,y,y}\) ^
2
we have a number 4 in common; look again and see how many xs they have in common
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