What is the equation for the vertical asymptote of the function shown below?
f(x)=3x^4-3/2x-5

A. x = 3/5
B. y = x3 - 2
C. x = 3/2
D. x = 5/2

Question

What is the equation for the vertical asymptote of the function shown below?
f(x)=3x^4-3/2x-5

A. x = 3/5 
   B. y = x3 - 2 
   C. x = 3/2 
   D. x = 5/2

amistre64 · Answer

vas are where the final factored form creates a zero in the denominator

anonymous · Answer

so i need to factor $$f(x)=3x^4-3/2x-5$$

amistre64 · Answer

3x^4-3     3(x^4-1)
------- = -------- ... i dont see any factors canceling soo
  2x-5          2x-5

2x-5 = 0 whent = x 5/2 right?

amistre64 · Answer

factoring helps to weed out the holes from the vas

amistre64 · Answer

holes are where the graph jumps of a spot; vas are where they slide up real close to it and shoot off into infinity

amistre64 · Answer

..jumps over a spot ....

anonymous · Answer

so i should plug in thte answers they gave me?

amistre64 · Answer

B is obviously not a VA if we stick to standard conventions of placements for the x and y axises

anonymous · Answer

or is the answer just 5/2?

amistre64 · Answer

Look for numbers that zero out the bottom; those are possible candidates for VAs

amistre64 · Answer

if the top and bottom factor and cancel out like terms; the ones that are left are VAs .... this one has no like terms to cancel, so anyting that zeros out the bottom is a VA

amistre64 · Answer

3/2 and 3/5 do not produce a zero for the bottom

5/2 does; so the VA is x=5/2

anonymous · Answer

oooh i see thanks!

amistre64 · Answer

youre welcome