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Mathematics 9 Online
OpenStudy (anonymous):

Does anyone know anything about square roots

OpenStudy (anonymous):

http://www.purplemath.com/modules/radicals.htm

OpenStudy (angela210793):

Wht do u want to know?

OpenStudy (amistre64):

tubers and such?

OpenStudy (anonymous):

I have this equation, its 3 square root symbol 27/y^6

OpenStudy (amistre64):

3sqrt(27) -------- ?? y^6

OpenStudy (anonymous):

yeah

OpenStudy (amistre64):

so the y^6 is not part of the radical correct?

OpenStudy (amistre64):

for clarification: \[\frac{3\sqrt{27}}{y^6}\]

OpenStudy (anonymous):

yeah

OpenStudy (anonymous):

that's it

OpenStudy (amistre64):

and you want to "simplify" perhaps?

OpenStudy (anonymous):

yeah

OpenStudy (amistre64):

sqrt(27) = sqrt(3*3*3) = sqrt(3^2) sqrt(3) = 3sqrt(3) 3*3sqrt(3) 9sqrt(3) --------- = -------- y^6 y^6

OpenStudy (amistre64):

most math notation has something that will undo it; the relationship between sqrt and ^2 cancel each other out

OpenStudy (amistre64):

so if you can determine a value in the sqrt(...) that can be factored as a ^2; go for it

OpenStudy (amistre64):

to make it easier to read: sqrt(27) sqrt(3*3*3) sqrt(3^2) * sqrt(3) 3 * sqrt(3)

OpenStudy (anonymous):

so now, it becomes 9 sqrt(3) ------- y^6

OpenStudy (anonymous):

is that it...

OpenStudy (amistre64):

thats as far as I can see to take it

OpenStudy (anonymous):

ok, cool... i have another one too... its the square root symbol 9x^6 ----- 64y^3

OpenStudy (amistre64):

sqrt(filler) is more readable

OpenStudy (amistre64):

sqrt(9 x^6) ---------- ; like thgis? 64 y^3

OpenStudy (anonymous):

yeah

OpenStudy (amistre64):

you should keep in mind that multiplication can split a radical like this: sqrt(9 x^6) sqrt(9) sqrt(x^6) ; now we can work on each of these in their own right

OpenStudy (amistre64):

what does sqrt(9) equal?

OpenStudy (anonymous):

is it 3

OpenStudy (amistre64):

3 it is; and for the x^6 part we have to know something about exponents. sqrt is another name for ^(1/2); which means sqrt(x^6) = x^(6/2) = x^3 altogether we get: 3 x^3 ------ 64 y^3

OpenStudy (anonymous):

ok, so now we try to find the square root of 64; right?

OpenStudy (anonymous):

ok.. i think i get it

OpenStudy (anonymous):

so its 3x^3 ----- 8y^3

OpenStudy (anonymous):

is that the final answer or is there more to simplify?

OpenStudy (amistre64):

if 64 is included in the radical; thats the umbrella of the sqaure root sign, then you would most likely convert it to 8 yes ... otherwise, leave it as is

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