Does anyone know anything about square roots
Wht do u want to know?
tubers and such?
I have this equation, its 3 square root symbol 27/y^6
3sqrt(27) -------- ?? y^6
yeah
so the y^6 is not part of the radical correct?
for clarification: \[\frac{3\sqrt{27}}{y^6}\]
yeah
that's it
and you want to "simplify" perhaps?
yeah
sqrt(27) = sqrt(3*3*3) = sqrt(3^2) sqrt(3) = 3sqrt(3) 3*3sqrt(3) 9sqrt(3) --------- = -------- y^6 y^6
most math notation has something that will undo it; the relationship between sqrt and ^2 cancel each other out
so if you can determine a value in the sqrt(...) that can be factored as a ^2; go for it
to make it easier to read: sqrt(27) sqrt(3*3*3) sqrt(3^2) * sqrt(3) 3 * sqrt(3)
so now, it becomes 9 sqrt(3) ------- y^6
is that it...
thats as far as I can see to take it
ok, cool... i have another one too... its the square root symbol 9x^6 ----- 64y^3
sqrt(filler) is more readable
sqrt(9 x^6) ---------- ; like thgis? 64 y^3
yeah
you should keep in mind that multiplication can split a radical like this: sqrt(9 x^6) sqrt(9) sqrt(x^6) ; now we can work on each of these in their own right
what does sqrt(9) equal?
is it 3
3 it is; and for the x^6 part we have to know something about exponents. sqrt is another name for ^(1/2); which means sqrt(x^6) = x^(6/2) = x^3 altogether we get: 3 x^3 ------ 64 y^3
ok, so now we try to find the square root of 64; right?
ok.. i think i get it
so its 3x^3 ----- 8y^3
is that the final answer or is there more to simplify?
if 64 is included in the radical; thats the umbrella of the sqaure root sign, then you would most likely convert it to 8 yes ... otherwise, leave it as is
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