Question

How would you simplify the following expression?
_ (4xy3)^2
(z4 )
The whole thing is surrounded by a large parentheses making the whole expression a negative with the power of 2

Answer 1

It's set up like a fraction or division problem

Answer 2

I keep coming up with 16x^2y^6z^-8 but I don't think thats right

Answer 3

could you type that up using the equation tool, i don't fully understand

Answer 4

I'm not sure how to make it work?????????????????

Answer 5

click equation tool in the bottom left of the text window and type away :)

Answer 6

i was trying, but I couldn't get it to come out the way it's supposed too

Answer 7

Thought this might be easier, I can attach a file....lol

Answer 8

ok is it \[-(4xy3/z4)^2\]

Answer 9

That looks right

Answer 10

looking at your attachment, you mean to the power of 3 and 4 i.e. \[−(4xy^3/z^4)^2 \]

Answer 11

its \[-(16x^2y^6)/z^8\]

Answer 12

would the z^8 be a negative too?

Answer 13

It's important to write the question like - (4xy3/z4)^2

(a/b)^2 = (a^2)/(b^2)
if the negative is outside the () such as - (bla)^2 then square bla and keep the neg.
if the negative is inside the () such as (-bla)^2 then don't keep the sign, it is positive.

Square all of the inside factors...

So I'm guessing the neg sign is outside all the ()...

So...

- {(9)16x^2 y^2) / (16z^2)} after squaring everything inside and now..
-(144x^2y^2 / 16z^2)

Answer 14

no, lilangl. and where did you get the extra 9, 101ryan101?

Answer 15

squared the 3

Answer 16

assuming it was a coeficient and not a power

Answer 17

lilangl wrote it wrong, its meant to be a power, look at the attached file

Answer 18

I'm sorry, now I know why you were confused......lol

Answer 19

thats fine :)

Answer 20

oh, then just add... x*x*x + x*x = x^5

Answer 21

what if the outside power is a negative?

Answer 22

if you have a negative power you take the reciprocal. sorry lilangl, what grade are you in?

Answer 23

and 101ryan101 i am afraid your x^5 thing is wrong, you would have to multiply them

Answer 24

Like this (4xy^3/z^4)^-2?

Answer 25

if the pwer is neg... bring it to the bottem of the fraction as a positive power like...

3^(-2) = 1/(3^2) it helps to write it on paper as a reciprocal to see better.

Answer 26

unfortunately college algebra, but I completely suck at algebra and always have.....I won't even need this stuff after I graduate

Answer 27

basically you can't make the power negative in this case

Answer 28

(4xy^3/z^4)^(-2) = {(z^4)/(4xy^3)} ^2 = (z^6)/(16x^2y^5)

Answer 29

hmmmm, my next problem is similar to the last one, but with a positive equation with a negative exponent. I think it would come out like this
(xy^6/4x^3y)^-2

Answer 30

yep

Answer 31

yea, if the whole thing is to a neg. power just flip it and keep the whole thing to the positive power then simplify

Answer 32

{ (bla1) / (bla2) }^(-2) = (bla2) / (bla1) ^2 ha ha ha