Question

can some one help me with this solving this equation that has rational expressions
x-3/x-1-2x-4/x-1=0

Answer 1

i do not think that there is a solution i keep coming up with 0 i just want to make sure that is correct

Answer 2

if you multiply everything under x-3 you are left with x-3 = 0
so x could be 3... as long as x isn't -5 or 1 because you don't want to divide be zero.
so one possible answer is 3. That's the best I can do right now...There seem to be various ways of manipulating but then you run into division by zero..

Answer 3

I say the answer is 3 but don't quote me on that..

Answer 4

x-3/x-1-2x-4/x-1=0 is this like this
(x-3)/(x-1)-(2x-4)/(x-1)=0 ? therefore
[(x-3)-(2x-4)]/(x-1)=0
-x-3+4=0(x-1)
-x+3=0
x=3

Answer 5

If the problem is: (x-3)/[(x-1-2x-4)/(x-1)]=0, then it becomes:

[(x-3)(x-1)]/(x-1-2x-4)=0
[(x-3)(x-1)]/(-x-5)=0
(x-3)(x-1)=0
x-3=0
x=3

x-1=0
x=1

If you substitute x=3 and x=1 into [(x-3)(x-1)]/(-x-5), then there is no division by zero and the answer equals zero for both values of x.