g(x)=x^2+8x+5
Does the function have a minimum or maximum value?

What is the function's minimum or maximum value?
Where does the minimum or maximum value occur?

Question

g(x)=x^2+8x+5
Does the function have a minimum or maximum value?

What is the function's minimum or maximum value?
Where does the minimum or maximum value occur?

anonymous · Answer

y'=2x=-8
x=-4

anonymous · Answer

I got -4
-11

anonymous · Answer

take the derivative..
g'(x) = 2x +8

then set that to zero

2x+8 = 0
x= -4

put -4 into the original equation

(-4)^2 +(-4)(8) + 5
16 -32 +5
-11

has a minimum at (-4,-11)

anonymous · Answer

It's quadratic with positive coefficients, so it will have a minimum, not a maximum. The location of the minimum is at (-4,-11) as shown above.

anonymous · Answer

$$\sqrt[3]{24}$$  my answer$$2\sqrt[3]{3}$$