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evaluate the line integral along the curve C
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\[\int\limits_{?}^{C}(y+z) ds, C is the straight-line segment x=0 y=3-t, z=t from (0,3,0) \to (0,0,3)\]
if f(x) = C and a and b are two numbers on the x-axis with a < b then the integral (area under the curve) is given as \[\int\limits_{a}^{b}f(x)dx\] where dx is a small change in x
sorry, I don't know what a line integral is.. opps. :)
i thought the line integral was \[\int\limits_{a}^{b}\sqrt{1+f'(x)^{2}}dx\]
it is
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