Solve the equation.
4 over x^2 − 2x − 35 = 5 over x^2 + 9x + 20
x=
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OpenStudy (anonymous):
do you only want an answer?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
PLEASE
OpenStudy (anonymous):
The roots will be imaginary
OpenStudy (anonymous):
KK
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OpenStudy (anonymous):
-11 + SQRT(99) i /2 ,-11 - SQRT(99) i /2
OpenStudy (anonymous):
that's the answer?
OpenStudy (anonymous):
They are the roots of euqtion
OpenStudy (anonymous):
x=51 ?
OpenStudy (anonymous):
x^2 +11x +55 = 0
D = 11^2 - (4*55) = 121 - 220 which is negative hence roots are imaginary
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OpenStudy (anonymous):
This is a place to learn, not get free answers.
OpenStudy (anonymous):
Is the eq: (4)/(x^2-2x-35) = (5)/(x^2+9x+20)
If so, you could be able to factor both eq... elminate (x-5) and solve for x, in this case, x=51.
OpenStudy (anonymous):
lol. im writing all their notes.....@LAZY
OpenStudy (anonymous):
Sorry >.>
OpenStudy (anonymous):
Move the RHS to the LHS.\[\frac{4}{x^2-2 x-35}-\frac{5}{x^2+9 x+20}=0 \]Then combine the fractions.\[\frac{51-x}{(x-7) (x+4) (x+5)}=0 \]By inspection, x = 51 .
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