Question

can someone help? differtiate4/[ln(2x^3-5)^3

Answer 1

http://www.wolframalpha.com/input/?i=differtiate4%2F%5Bln(2x^3-5)^3

Answer 2

that the sound of the men.. working on the chain..

Answer 3

Yes use the chain rule.
Try to really break it down into more manageable functions:
Say
\[w = \frac{4}{u^{3}} \rightarrow dw = -\frac{12}{u^{4}}\]
\[u = \ln v \rightarrow du = \frac{1}{v}\]
\[v = 2x^{3}-5 \rightarrow dv = 6x^{2}\]
Then put it all together in terms of x
\[f'(x) = dw*du*dv = -\frac{72x^{2}}{v*u^{4}} = -\frac{72x^{2}}{(2x^{3}-5)*\ln^{4}(2x^{3}-5)}\]