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OpenStudy (anonymous):
solve the initial value problem differential equation : dr/dt=(sec^2t)i+(4t^3+8)j initial condition r(0)=-8j
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OpenStudy (dumbcow):
\[\int\limits_{}^{}dr = \int\limits_{}^{}\sec^{2} t+ 4t^{3}+8 dt\] \[r = \tan t + t^{4}+8t + C\] \[r(0) = 0+C = -8 \] \[r= \tan t + t^{4}+8t -8\]
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