Which of the following could be an example of a function with a range (-∞,a] and a domain [b, ∞) where a < 0 and b < 0? A. ƒ(x)= √(x-a)+b B. ƒ(x)=3√(x-b)+a C. ƒ(x)=-3√(x+a)-b D. ƒ(x)=-√(x+b)-a
Where do the radicals end? I'm guessing right after the parenthesis?
yes
Well, let's look at the range first. That square root part is always non negative, right?
So looking at each possibility: A. ƒ(x)= √(x-a)+b To find the lowest that could be, set the whole radical to 0. So b is the lowest. And as we increase that radical, the whole function can get as high as we want. So that's (b, infinity) B. ƒ(x)=3√(x-b)+a Setting the radical to 0 gives a as the lowest possibility for the range. C. ƒ(x)=-3√(x+a)-b Radical to 0 gives -b as the highest possibility, since the whole radical is multiplied by a negative and will decrease the function as it increases. D. ƒ(x)=-√(x+b)-a Radical to 0 will give -a as the highest possibility.
Any chance you mistyped a negative sign in the problem somewhere? Perhaps before an a? Left one out, or else included one that should have been left out?
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