Ask your own question, for FREE!
Mathematics 19 Online
OpenStudy (anonymous):

Which of the following could be an example of a function with a range (-∞,a] and a domain [b,∞) where a < 0 and b < 0? A. f(x)=√x-a+b B. f(x)=^3√(x-b)+a C. f(x)=-^3√x+a-b D. f(x)=-√x+b-a (the root only covers the first two variables in each answer choice)

hero (hero):

Kassia...quick question...

OpenStudy (anonymous):

what?

hero (hero):

Is it :\[f(x) = \sqrt{x-a+b}\] or \[\sqrt{x} -a+b\]

hero (hero):

for the first one...

OpenStudy (anonymous):

in between it covers the first tw ovariables

hero (hero):

Okay....yeah, I just saw what you wrote about the root covering the first to variables...thanks

OpenStudy (anonymous):

any idea how to answer it??

hero (hero):

Working on it

OpenStudy (anonymous):

thanks!@

hero (hero):

Apparently, an easier way to figure this out is by using actual numbers for a and b. They're both negative so, if a = -3 and b = -5....you can use that to help figure this out

hero (hero):

Have you tried it yet, or do you want me to explain further using examples?

hero (hero):

Kassia, what are you doing? lol

hero (hero):

Kassia, are you there?

hero (hero):

Okay, well, the answer is D

hero (hero):

I can show you why...

OpenStudy (anonymous):

sorry i had to make a copy, so i need to just plug in those variables and then i can get the answer?

OpenStudy (anonymous):

sorry i had to make a copy, so i need to just plug in those variables and then i can get the answer?

OpenStudy (anonymous):

sorry i had to make a copy, so i need to just plug in those variables and then i can get the answer?

hero (hero):

Well,no, it doesn't exactly work like that. I'd have to explain it

hero (hero):

This is more than just plug and play

hero (hero):

First of all we not only do we need to choose numerical a and b, we also have to find an x in the appropriate range between b and infinity

hero (hero):

And we have to test them all out, but there's an interesting twist to it.

hero (hero):

It involves the cube roots. You can take the cube root of a negative number, but you can't take the square root of a negative number...

hero (hero):

So when we test these out, we have to take that into consideration

hero (hero):

So when we we're testing out the cube roots, we'll use x = -32 and x = 22

hero (hero):

We're looking for an x, a, and b such that when we evaluate them, it will give us the appropriate range

hero (hero):

We obviously can only use x = 22 for the square root functions so if you choose a = -3 and b = -5, you will see that the only thing that works is D

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!