Which of the following could be an example of a function with a range (-∞,a] and a domain [b,∞) where a < 0 and b < 0? A. f(x)=√x-a+b B. f(x)=^3√(x-b)+a C. f(x)=-^3√x+a-b D. f(x)=-√x+b-a (the root only covers the first two variables in each answer choice)
Kassia...quick question...
what?
Is it :\[f(x) = \sqrt{x-a+b}\] or \[\sqrt{x} -a+b\]
for the first one...
in between it covers the first tw ovariables
Okay....yeah, I just saw what you wrote about the root covering the first to variables...thanks
any idea how to answer it??
Working on it
thanks!@
Apparently, an easier way to figure this out is by using actual numbers for a and b. They're both negative so, if a = -3 and b = -5....you can use that to help figure this out
Have you tried it yet, or do you want me to explain further using examples?
Kassia, what are you doing? lol
Kassia, are you there?
Okay, well, the answer is D
I can show you why...
sorry i had to make a copy, so i need to just plug in those variables and then i can get the answer?
sorry i had to make a copy, so i need to just plug in those variables and then i can get the answer?
sorry i had to make a copy, so i need to just plug in those variables and then i can get the answer?
Well,no, it doesn't exactly work like that. I'd have to explain it
This is more than just plug and play
First of all we not only do we need to choose numerical a and b, we also have to find an x in the appropriate range between b and infinity
And we have to test them all out, but there's an interesting twist to it.
It involves the cube roots. You can take the cube root of a negative number, but you can't take the square root of a negative number...
So when we test these out, we have to take that into consideration
So when we we're testing out the cube roots, we'll use x = -32 and x = 22
We're looking for an x, a, and b such that when we evaluate them, it will give us the appropriate range
We obviously can only use x = 22 for the square root functions so if you choose a = -3 and b = -5, you will see that the only thing that works is D
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