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PLease help look at link
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b
i did it simply by finding the angle whose sin is 11/14 then dividing the result by 2 . then finding the sine of that.
is b...
just multiply sin\[\theta\]/2 and cos\[\theta\]/2 and equal to 11/28
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because\[\sin \theta =2\sin \theta/2 *\cos \theta /2 and\]
i think this formula can help u alot :\[\sin ^2+\cos ^2=1\] and we will use in this problem this shape of the formula: \[\sin =\sqrt{1-\cos ^2}\] and also \[\cos =\sqrt{1-\sin ^2}\]
11/(14*2) and the \[\theta\] is in 90 then both sin and cos will be possitive....
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