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Mathematics 21 Online
OpenStudy (anonymous):

PLease help look at link

OpenStudy (anonymous):

OpenStudy (anonymous):

b

OpenStudy (anonymous):

i did it simply by finding the angle whose sin is 11/14 then dividing the result by 2 . then finding the sine of that.

OpenStudy (anonymous):

is b...

OpenStudy (anonymous):

just multiply sin\[\theta\]/2 and cos\[\theta\]/2 and equal to 11/28

OpenStudy (anonymous):

because\[\sin \theta =2\sin \theta/2 *\cos \theta /2 and\]

OpenStudy (anonymous):

i think this formula can help u alot :\[\sin ^2+\cos ^2=1\] and we will use in this problem this shape of the formula: \[\sin =\sqrt{1-\cos ^2}\] and also \[\cos =\sqrt{1-\sin ^2}\]

OpenStudy (anonymous):

11/(14*2) and the \[\theta\] is in 90 then both sin and cos will be possitive....

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