Given the circle with radius 12, what is the probability of choosing a point inside the triangle?
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OpenStudy (anonymous):
OpenStudy (anonymous):
This one looks fun. To find the probability we need
P = area of triangle/ area of circle
OpenStudy (anonymous):
Let's start with the circle. Do you know the area formula for any circle?
OpenStudy (anonymous):
no
OpenStudy (anonymous):
A = pi * r^2
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OpenStudy (anonymous):
ok
OpenStudy (anonymous):
so what area do you get?
OpenStudy (anonymous):
113.09
OpenStudy (anonymous):
not quite.
A = 3.14*12*12= ?
OpenStudy (anonymous):
452.16
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OpenStudy (anonymous):
sooo?
OpenStudy (anonymous):
there we go. now we have the tricky part of the triangle. Since I assume that is a central angle we know it is the same angle in the triangle as the arc. See attached picture.
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
Our triangle area is
\[A = 1/2 b*h\]
we have to solve for both of those first and we can use the 30 - 60- 90 pattern
OpenStudy (anonymous):
ok
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OpenStudy (anonymous):
that gives us h= 6
and half the base is 6sqrt3 (since we split the triangle in half)
The total base is 12sqrt3
OpenStudy (anonymous):
ok so how do we turn that into prob.?
OpenStudy (anonymous):
We have to finish with the area of the triangle first.. then the probability is
area triangle / area circle
the area of the triangle ends up being 36 * sqrt 3
OpenStudy (anonymous):
So the probability is
\[P=36\sqrt{3}/452.16\]
OpenStudy (anonymous):
thank you sooo much
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