Question

Solve for r.
r^2 +3r=7

Answer 1

-b +- root(b^2 -4(a)(c)) all over 2(a)
with
a=1
b=3
c=-7

Answer 2

\[r^2+3r-7=0\]
use
\[r=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\] with
\[a=1,b=3,c=-7\]

Answer 3

the answer was
-3+sqrt37/2, -3-sqrt37/2
I'm confused

Answer 4

notice in satellite's post that when you substitute into the quadratic formula, you get two possible answers.

for the portion of the formula b^2-4ac = (3^2) -4*1*-7=9+28=37

so we get
\[r= (-3\pm \sqrt{37})/ 2\]