Write and equation for the line in slope-intercept form.
Passing through (5,2) and parallel to the line whose equation is y=-7x+6.

Question

anonymous · Answer

When you have an equation of a line in the form of $y=mx+c$, you can take the slope as being the number in front of the $x$ term.

Then you can use the equation of a line formula:
$y-y_1=m(x-x_1)$

anonymous · Answer

I know the answer is y=-7x+37, I'm just trying to figure out how to get there.

anonymous · Answer

well use the equation of a line formula dalvoron gave you, along with the information provided in the problem. In order to have a line that is parallel they must have the same slope, in this case the slope is m=-7 and we have the points (5,2) (x1,y1) now you just plug in and solve for y

anonymous · Answer

Thank you, you beautiful man.

anonymous · Answer

So we are already given the slope from the parallel line $$m=-7$$
We also know that the equation of a line is $$y=mx+b$$And we know an (x,y) coordinate (5,2)

We can plug in the coordinate point and the slow into the line equation and solve for b:$$y=mx+b$$$$b=y-mx$$Plug in x, y, and m:$$b=5-(-7)(2)$$$$b=19$$

Thus$$y=-7x+19$$

anonymous · Answer

y-2=-7(x-5)
y-2=-7x+35
y=-7x+37

anonymous · Answer

y-2=-7(x-5)
y-2=-7x+35
y=-7x+37

anonymous · Answer

b=2-(-7)(5)