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Mathematics 18 Online
OpenStudy (anonymous):

http://trickiestofall.blogspot.com/2011/07/chessboard-square-and-rectangle-count.html

OpenStudy (anonymous):

I asked the rectangle one a few days ago. Let's see if anyone remember the solution :)

OpenStudy (anonymous):

do u?

OpenStudy (anonymous):

My answer is \[\sum_{n=1}^8 \sum_{m=1}^8 (9-m)(9-n)\], which is 1296

OpenStudy (akshay_budhkar):

i answered it!!! last time!!

OpenStudy (anonymous):

There was a solution which didn't involve a summation though.

OpenStudy (anonymous):

Do you remember the formula you posted Akshay?

OpenStudy (akshay_budhkar):

[(n)(n+1)/2]^2 i believe

OpenStudy (anonymous):

Indeed!

OpenStudy (akshay_budhkar):

for n*n chessboard

OpenStudy (akshay_budhkar):

dats 1296 for 8*8

OpenStudy (anonymous):

And for a m*n chessboard, it expands to \[\frac{(m)(m+1)}{2}\times \frac{(n)(n+1)}{2}\]

OpenStudy (akshay_budhkar):

yes.. right dalvoron..

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