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Find an equation of the parabola which passes through the points (1,3) and (-2,0). Please do it step-by-step...
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Basic form is y^2 = 4ax. This parabola goes through x is -2 so basic form is y^2 = 4a(x+2) Now use (1,3) to get a 9 = 4a(3) -> a=3/4 so y^2 = 3(x+2)
you need 3 points to fix a parabola to a plane
and we prolly need to assume its not a rotatation
In general that's true but what else can one do given the question, except assume a basic parabola in standard position and then translate it.
there are infinite parabolas passing through these points
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oh i dont deny we need to make some sort of assumption; but the question itself is messed up. There is no "correct" answer, even tho there are plenty of wrong answers :)
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