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The period of f(x)=cos (2pi/3)x is
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\[\cos (2\pi/3)x\]
cos x has a period of 2pi. with a multiple of K this will have a multiple of 1/k. so, 3/2pi . 2pi ie 3
if you're specific about the rigor, period means that \[\cos ( 2\Pi \div3 (x+\alpha)) = \cos ( 2\Pi \div3 (x))\] . this gives \[2 \pi \div 3 \alpha = 2 \pi\] . so \[\alpha\] equals 3. Cheers!
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