can someone rationalize this? sqrt2 - 1 all over sqrt 6
Okay I would advise you to Multiply and Divide by sqrt2 + 1
\[(\sqrt{2}-1/\sqrt{6}) * (\sqrt{6} /\sqrt{6}) \]
Why ishaan? there is only sqrt6 in the denominator
ah understood the question wrong sorry
no worries
I took denominator as sqrt2 - 1
so do i multipy top and bottom by sqrt 6?
Lammy, can you multiply that? give it a shot
yes, that will eliminate the sqrt in the denominator
ok got it so rationalize is just geting rid of sqrt on the denominator
yes also, your instructor will probably want you to simplify that numerator after you distribute the sqrt6 to the numerator.. so keep that in mind as well
yea = 2sqrt3-sqrt6 all over 6
perfect, well done
thanks!
anytime
ishaan was right, but the question was wrong ;)
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