y'+y=(y^2)(e^x)
What do you need to do with it?
Solve the differential equation
Its non-linear :/ That means unless its separable its not too easy to solve.
That's strange cause this problem is under the section linear first order differential eqs
Hmmm...let me look at it for a minute.
its a first-order nonlinear ordinary differential equation :)
Yeah, the non-linear is throwing me off
i cannot believe the huge crash tonight almost 3 hours it seems
yeah, what else are we supposed to do with our time?
i have been wanting to post that attachment forever
lolol
i was like omg i cant post it i kept checking every second
lol now i gotta go watch a movie
have fun!
I was trying to put v = 1/y -> v' = y'/y^2 when I got kicked...
How about if u have f(x)y instead of y (say xy) in the original equation?
are you saying this (xy)'=y^2e^x?
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