Question

Factor completely:

c2 - 10c - 24

Answer 1

sorry, c^2 - 10c - 24

Answer 2

\[(c-12)(c+2)\]

Answer 3

right.

Answer 4

how did you get that? I still have two more to do and I want to try to do them

Answer 5

could you walk me through it?

Answer 6

ok so you need two numbers A and B such at AB=the last term in your quadratic and A+B= the middle term in your quadratic given your c^2 has no coefficants

Answer 7

take your last term break it down into its factoring groups like 24 was 1*24 or 2*12 or 3*8 or 4*6 so i know i can make 10 with two of those (2*12 or 6*4) and since i got a negative in the last term i can rule out 6*4 cause -6+-4 =-10 but -6*-4=24 not -24 so 12*2 is the last option and you arrange the the numbers with the - sign and the postive sign to make that middle term work

Answer 8

To try to make it more clear:

You are looking for some kind of factored form like:
(c + a)(c + b)

Well if we multiply those two out (using foil or regular distribution) you get:

c^2 + ac + bc + ab

Then we combine those two middle terms:

c^2 + (a+b)c + (a*b)

Now compare that to the expression you started with:
c^2 + (a+b)c + (a*b)
= c^2 -10c - 24

And we can see that a+b = -10
And that a*b = -24

Once we have those two equations we can solve for a and b, and plug them back into our original:

(c+a)(c+b) will be the factored form.

Answer 9

ty