divide (2x^3-x^2+3x-1)/(x+2)

Question

anonymous · Answer

you need more medals for making it look as nice as it does lol

myininaya · Answer

lol
i think the person left before anyone could answer

myininaya · Answer

oh wait maybe he is here i dont know

anonymous · Answer

$$2 x^2-5 x+13 \text{ with } a \text{ remainder} \text{ of } -27 $$$$\left(\left(2 x^2-5 x+13\right)(x+2)\right)-27 = 2 x^3-x^2+3 x-1  $$

myininaya · Answer

2x^2 -5x+13
          --------------------------------
x+2 |      2x^3       -x^2        +3x           -1
         -  (2x^3      +4x^2)
          -----------------------------------
                            -5x^2     +3x      -1
                          -(-5x^2   -10x)
                          -------------------------
                                         13x-1
                                      -(13x-26) 
                                  ----------------
                                                  25

myininaya · Answer

thats for correcting my quotient but i believe 25 is the right remainder

anonymous · Answer

@myininaya Believe all you want Sir. You have made an error in the last multiplication. 13 * (x + 2) is (13x + 26), not (13x - 26) . (13x -1) - (13x + 26) = -27 , the remainder. Refer to the "show steps" in the fourth pane at: http://www.wolframalpha.com/input/?i=divide+%282x^3-x^2%2B3x-1%29%2F%28x%2B2%29

myininaya · Answer

yep i made a mistake 13(x+2) is not 13x-26 
its 13x+26
ok you are right
i didn't see that
i'm not a sir

myininaya · Answer

also if you just tell me my mistake i will believe you
its not what i believe
i just thought my math was right
so thanks for showing my error and thats all you have to do to make me believe you lol

anonymous · Answer

Thank you for taking the time to respond.  I have posted inadvertent mistakes my self on this math site.  Sorry regarding the Sir usage.  Perhaps the whole sentence could be viewed as a bit edgy.  No was harm intended.