Question

Differenciate y= (2sin(x+1))^1/2, show steps

Answer 1

http://www.twiddla.com/589515
come here

Answer 2

dy/dx=(1/2)(2cos(x+1).(1))^(-1/2)
dy/dx=1/(cos(x+1))^(1/2)

Answer 3

\[y=(f(g(x)) => y'=g'(x)f'(g(x))\]
thats not right bell

Answer 4

i just worked it out using the chain rule lol

Answer 5

\[y'=\frac{1}{2}(2\sin(x+1))^{\frac{1}{2}-1}(2\sin(x+1))'\]
\[y'=\frac{1}{2}(2\sin(x+1))^{\frac{-1}{2}}*2(\cos(x+1))\]

Answer 6

myininaya: huhu.. thanks 4 correct me.. after this i won't do wrong again..

Answer 7

yep, that is the correct answer LOL

Answer 8

lol dont worry
we all make mistakes

Answer 9

i gave you a medal bellz :)