Question

evalute the integral

Answer 1

\[\int\limits_{-\infty}^{-2}2dx/(x^2-1)\]

Answer 2

what does tht mean?

Answer 3

what u asked?

Answer 4

got ur question.haha..

Answer 5

ok wanna solve it?

Answer 6

the indefinte integral is ln(x^2-1)

Answer 7

HINT ; whenever there is Infinty ... try to get rid of INfinty by Substituting 1/x as something

Answer 8

it is not ln.. coz on numerator there is no 2x

Answer 9

i cant solve it

Answer 10

in this case however partial fractionize the given ter m into (1/x-1) -(1/x+1)

Answer 11

-ln(3)

Answer 12

ok ,got it now

Answer 13

what a easy question it was , i challenged myself ))

Answer 14

1.09861

Answer 15

\[2\int\limits_{-\infty}^{-2}dx\(x^2-1)\]
\[2.1\2\left[ \log(-2-1)\(-2+1) \right] -2/2\left[ \log(-\infty-1)\(-\infty+1) \right]\]
log3

Answer 16

thanks to all contributors