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Mathematics 14 Online
OpenStudy (anonymous):

radius of convergence

OpenStudy (anonymous):

\[\sum_{n=0}^{\infty}(x-2)^n/10^n\]

OpenStudy (anonymous):

heyy help

OpenStudy (anonymous):

i am confused about this radius

OpenStudy (anonymous):

when the radius is infinite

OpenStudy (anonymous):

radius of convergence is the value of x upto which the above series is convergent {i.e. Following values of the series are smaller than the initial values }

OpenStudy (anonymous):

8

OpenStudy (anonymous):

book says 10

OpenStudy (anonymous):

any series is convergent if the term yields <1 value .. hence (x-2)/10<1 ; X<12 hence 12 is radius of convergence

OpenStudy (anonymous):

you want: \[\left| \frac{x-2}{10} \right|< 1\]

OpenStudy (anonymous):

yes joe

OpenStudy (anonymous):

soory calc mistake

OpenStudy (anonymous):

do u find 10 phaniraj?

OpenStudy (anonymous):

so you get: \[\left| \frac{x-2}{10} \right|<1 \Rightarrow -1< \frac{x-2}{10} < 1 \Rightarrow -10<x-2<10\]\[-8<x<12\]

OpenStudy (anonymous):

so x can be inbetween -8 and 12, giving an interval radius of 10. (the whole interval is 20 units long)

OpenStudy (anonymous):

joe i got nowww ,oh thanks

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