Question

How would I graph:

y = ( x + 2)^2 + 1

Answer 1

It will have an asymptote on the x axis when y=1 and it will cross the y axis at 5. After that just try plugging in a few values and see what comes up.

Answer 2

A really rough example is it could look a bit like this:

Answer 3

Thanks.. Question..Where did u get the 1 and 5 from?

Answer 4

That example if really "rough"

Answer 5

oh

Answer 6

it dosent even resemble the acutal graph

Answer 7

We can agree that this is a parabola correct

Answer 8

yes

Answer 9

Now, the center of the parabola is gonna be centered at the point -2,1

Answer 10

That is where the vertex is

Answer 11

How do we get that ? Well its from the equation: (x+2)=0, solving for x we get x=-2, this is the x coordinate, the y coordinate of the vertex is simply the +1. So that is how we get the vertex at (-2,1)

Answer 12

OH :O

Answer 13

Now, with respects to this function crossing the y axis at 5, that is correct, to prove that we simple set x to equal zero in the orginal equation (x+2)^2+1. Doing that gives us 5 or (0,5)

Answer 14

Rember that the reason this parabola is at (-2,1) is becuase of the plus 1, which means that we shift the function 1 unit to the left.

Answer 15

k

Answer 16

Here is a sketch:

Answer 17

k :)

Answer 18

thanks

Answer 19

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