uggggh:
using half-angle identities to evaluate cos(π/8) exactly...
I did cos(π/8) = cos (π/4/2) = +-√(1+cos(π/4)/2) = (-sin(π/4))/2....
Am I already wrong?
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OpenStudy (anonymous):
the question just asks to use half-angle identites to find the exact measure of cos(pi/8)
OpenStudy (anonymous):
no what you doing is right
OpenStudy (anonymous):
www.sosmath.com/trig/douangl/douangl.html
- tells u all about it there
OpenStudy (anonymous):
so does sqr(1+cos(pi/4)) = -sin(pi/4) ?
OpenStudy (anonymous):
Yeah just cos pi/4 = sqrt(2)/2
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OpenStudy (anonymous):
sqr(1+cos(pi/4)) is not equal to -sin(pi/4)
OpenStudy (anonymous):
why you get involved the sinus you know the value of cosPI/4 put that in equation then reach the cosPI/8
OpenStudy (anonymous):
the value of cos(pi/4) is not an exact measure tho
OpenStudy (anonymous):
the value of cos(pi/8) isn't an exact measure either
OpenStudy (anonymous):
right....but the question says to "use the half-angle identities to evaluate cos(pi/8) exactly"