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The function ƒ(x)=a^x+4 will never cross the x-axis. A. True B. False
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True
Have you tried graphing this for various values of a? Geogebra can do this quickly and easily. (and freely).
thank you, and yes i did i just didnt know if that was how to actually do it or not
http://www.wolframalpha.com/input/?i=plot+y%3D5%2C+y%3D2^x%2B4%2Cy%3D3^x%2B4%2Cy%3D4^x%2B4
If you try solving 0 = a^x + 4 for x You will have log base a of -4 = x But you can't have a negative base to a logarithm. (that's how it's defined. :)
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You can have negatives in a log :P (digresses)
True true. But we want the log function to be single-valued and return a real result. :)
Yeap :P
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