Question

lim(x->-2) (x+1)/((x^2)+4x+3)

Answer 1

the denominator can be factored into (x+1)(x+3) so you can re-write it as
lim (x-->-2) [(x+1)/(x+1)(x+3)]
We can cancel the (x+1) binomials to get 1/(x+3)
Now just substitute x for -2 and you should get
lim (x-->-2) [1/(x+3)]=1/(-2+3)=1/1=1
Hope this helps :)

Answer 2

thx

Answer 3

No problem ;)