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Use the Laws of Logarithms to expand the expression.
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\[\log_{6} (x \sqrt{y})\]
\[\log_6(x \sqrt{y})=\log_6(x)+\log_6(y^{\frac{1}{2}})=\log_6(x)+\frac{1}{2}\log_6(y)\]
\[\log_{6} (x) + \log_{6} \sqrt{y} = \log_{6} (x) + \log_{6}y ^{1/2} = \log_{6} (x) + (1/2)\log_{6}y\]
which is it?
they are both the same... we were racing.. just a bit different "looking" but they are the same... I'd go with his because it's easier to read then mine...
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learning log properties can be a challenge...
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