Question

how do i solve 2sinxcosx+2sinx-cosx-1=0?

Answer 1

i am at (1/2)sin2x+sinx=(1+cosx)/2

Answer 2

@sat - i'm hesitant to take the root of both sides, making the right side cos(x/2)

Answer 3

probably some gimmick give me a minute

Answer 4

oh gimmick is it factors

Answer 5

try factoring
\[2xy +2x-y-1\]

Answer 6

i don't see it :O(

Answer 7

2x(y+1)-(y+1)=(2x-1)(y+1)=2sin(x)-1)(cos(x)+1)

Answer 8

once you scratch your head for a while you will get \[(2x-1)(y+1)\]

Answer 9

So wherever sin(x)=1/2 and cos(x)=-1.
If you are looking at [0,2pi] Your solutions are pi, pi/3,2pi/3

Answer 10

what malevolence said. then you see
\[(2\sin(x)-1)(\cos(x)+1)=0\]
\[\sin(x)=\frac{1}{2}\] or
\[\cos(x)=1\]

Answer 11

i'm afraid i can't follow the type :(

let me see if i can factor it on my own tho
good lookin' out

Answer 12

if you are seeing gibberish refresh your browser. then you will see the latex

Answer 13

maybe you will see some pellets there too, who knows. pellets. ho ho ho

Answer 14

refreshing should work though. will look nice

Answer 15

@sat - why do you have cosx=1 and not -1 ?

Answer 16

in any event i got x = 150deg