How would I show my work to make this true? x = -5 , x = 2 x^2 +3x -10 =0
its asking if x=-5 and x=2 are solutions to the equation x^2+3x-10=0 to prove this is true, factor the given equation (by whatever method you want) and you will arrive at the factored equation (x+5)*(x-2)=0, which shoes solutions of x=-5, 2, proving given data
shows*
So is this enough steps shown, or am I missing steps to prove the answer? (x+5)*(x-2)=0 x^2 +3x -10 =0
my bad..
for what?
that would be plenty for any teacher i have ever had
Oh, I just thought they were expressions not equations... I to concentrate a little more..
Sweet. I just wanted to make sure I had it right.
if you really want to show more work, you can use the quadratic equation to validate your a and b values in the factored expression, but idk if your prof would really require that
Idk either. My teacher is strict and constantly picks at me lol
if thats the case, i would recommend the quadratic equation, its easy and keeps profs off your back when they want to be mean
How do I do that?
That's what it's suppose to be is a quadratic equation. I wasn't thinking
for an equation of the form Ax^2+Bx+C=0, the quadratic equation is \[(-B \pm \sqrt{B^2-4*A*C})/(2*A)\]
so B=3, A=1, C=-10, solving it should get you 2 and -5 really easily
It looks like a foreign language lol Unfortunately, I have to try and re-learn all this every single day.
ill walk you through it if you want
That would be awesome!
A=1, B=3, C=-10 so (−B±√B2−4∗A∗C)/(2∗A) becomes (-3±√ (3^2-4*1*-10))/(2*1) (-3±√(9+40))/2 (-3±√49)/2 (-3±7)/2 this gets you two answers out of the + and the -, for the -, it becomes (-3-7)/2 -10/2 -5 for the + you get (-3+7)/2 4/2 2 so your answers are -5 and 2
well, x=-5 and x=2 if you want to be explicit
Wow! Thank you so much! I wish I could give you another medal :)
thanks, i really enjoy helping out ^^
:)
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