Question

Log7x = 1/3log7 64 + 1/2log7 121. How do you solve for x?

Answer 1

\[\log_{7}x = \log_{7}64 + 1/2\log_{7}121 \]

Answer 2

There is a 1/3 infront of log7 64, sorry.

Answer 3

if 1/3 is there the answer is x=44;
if x/3 is not there then ans: x=64*11

Answer 4

How, though?

Answer 5

use two formulas:
m*log(a)=log(a^m);
log(a)+log(b)=log(a*b)

Answer 6

Thank you, Ryan. (:

Answer 7

NP