Question

Find the maximum or minimum value of the function defined by f(x)=-x^2-6x-8

Answer 1

the maximum or minimum value is the vertex of the function

Answer 2

do -b/(2a)
and then do f(-b/(2a))

Answer 3

the value of x^2 is in -ve so sad face.. Max point.

Answer 4

Of the value of x^2 is in +ve, then there will be a happy face.. Min Point,

Answer 5

Now judge yours!

Answer 6

maximum of two

Answer 7

f(-(-6)/2(-1))=f(6/(-2))=f(-3)=-(-3)^2-6(-3)-8

Answer 8

i dont get 2

Answer 9

i get 1 we can also do it another way but it is longer
f(x)-(x^2+6x)-8=-(x^2+6x+9)-8+9
=-(x+3)^2+1
vertex is (-3,1)
the max value is 1