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Please help simplify this expression and assume all variables are real numbers 5 to the square root of 32(x+4)^5
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it must be 5th root of 32(x+4)^5. the answer then is 2(x+4)
\[\sqrt[5]{32(x+4)^5}=2(x+4)\]
Yes you are right. Sorry I don't have the symbols to use
can you show me or explain how you got that answer please?
\[\sqrt[5]{32(x+4)^5}=\sqrt[5]{2^5(x+4)^5}=2(x+4)\]
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did u get it? u 2 to the power 5 and (x+4) to the power 5 under the 5th root.
I think I got it. The power of 5 under the 5th root cancel each other out? Is that right?
yes..you got it :)
Cool. Thank you sooo much. I appreciate your help.
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