hi . is this thing for real ?
\begin{array}l\color{#352486}{\text{N}}\color{#79a422}{\text{o}}\color{#585837}{\text{ }}\color{#32a621}{\text{i}}\color{#795a8a}{\text{t}}\color{#332986}{\text{ }}\color{#747a71}{\text{i}}\color{#a7338a}{\text{s}}\color{#234826}{\text{n}}\color{#317526}{\text{t}}\color{#761587}{\text{.}}\color{#257416}{\text{}}\end{array}
Well anybody knows really interested in polar coordinates ?
LOL.
we are having party now!
HAHA saif!!
c'mon guys I need to know something about polar coordinates , anybody up for help?
Celebrate Party!
motior asks the question
okay whatever : if anybody is interested answer the following question . why is the value of " r " in the polar curve r = cos theta is always positive .
because you can't have negative radius
no my question is theta is -ve in 2nd and 3rd quadrant so r must be -ve out there .
a graph of r = cos theta just shows half of the picture
nope, r is magnitude which is never negative
you get nice looking circle r=cos theta
how would you plot r = cos theta
it is circle that starts at y axis
well r = (x^2 + y^2 ) ^0.5 and when r is +ve we only draw its curve but when its -ve we don't care , why ?
hello ???
boom boom anybody ????
oh nvm
how do u find r ? using x and y ofcourse
http://tutorial.math.lamar.edu/Classes/CalcII/PolarCoordinates.aspx this article turned me mad .
okay whatever thanks for trying me to help , I should ask my teacher
Okay, when we change from cartesian system to polar system, we make some changes. In cartesian , we describe a point using (x,y) for example (-2,1) when we change it to polar we want it in terms of (r, theta) , r represent distance from origin, theta represent angle from orgin Using distance formula = r=Sqrt[5] theta = arctan(1/2)=about 26 degree since we know it is 180-26=154 degree (sqrt[5],154 degree)
Join our real-time social learning platform and learn together with your friends!