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OpenStudy (anonymous):

hi . is this thing for real ?

OpenStudy (saifoo.khan):

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OpenStudy (anonymous):

Well anybody knows really interested in polar coordinates ?

OpenStudy (saifoo.khan):

LOL.

OpenStudy (saifoo.khan):

we are having party now!

OpenStudy (lalaly):

HAHA saif!!

OpenStudy (anonymous):

c'mon guys I need to know something about polar coordinates , anybody up for help?

OpenStudy (saifoo.khan):

Celebrate Party!

OpenStudy (anonymous):

motior asks the question

OpenStudy (anonymous):

okay whatever : if anybody is interested answer the following question . why is the value of " r " in the polar curve r = cos theta is always positive .

OpenStudy (anonymous):

because you can't have negative radius

OpenStudy (anonymous):

no my question is theta is -ve in 2nd and 3rd quadrant so r must be -ve out there .

OpenStudy (anonymous):

a graph of r = cos theta just shows half of the picture

OpenStudy (anonymous):

nope, r is magnitude which is never negative

OpenStudy (anonymous):

you get nice looking circle r=cos theta

OpenStudy (anonymous):

how would you plot r = cos theta

OpenStudy (anonymous):

it is circle that starts at y axis

OpenStudy (anonymous):

well r = (x^2 + y^2 ) ^0.5 and when r is +ve we only draw its curve but when its -ve we don't care , why ?

OpenStudy (anonymous):

hello ???

OpenStudy (anonymous):

boom boom anybody ????

OpenStudy (anonymous):

oh nvm

OpenStudy (anonymous):

how do u find r ? using x and y ofcourse

OpenStudy (anonymous):

http://tutorial.math.lamar.edu/Classes/CalcII/PolarCoordinates.aspx this article turned me mad .

OpenStudy (anonymous):

okay whatever thanks for trying me to help , I should ask my teacher

OpenStudy (anonymous):

Okay, when we change from cartesian system to polar system, we make some changes. In cartesian , we describe a point using (x,y) for example (-2,1) when we change it to polar we want it in terms of (r, theta) , r represent distance from origin, theta represent angle from orgin Using distance formula = r=Sqrt[5] theta = arctan(1/2)=about 26 degree since we know it is 180-26=154 degree (sqrt[5],154 degree)

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