I just need a concept on how to solve this!

Find the equation of the tangent line to the circle (x^2)+(y^2)=2 and passing through (6,4)

Thanks.

Question

I just need a concept on how to solve this!

Find the equation of the tangent line to the circle (x^2)+(y^2)=2 and passing through (6,4)

Thanks.

anonymous · Answer

that enough? concept is find the slope via the derivative, then use point slope form

anonymous · Answer

I don't get it... the formula is so hard to understand.

anonymous · Answer

are you familiar with implicit differentiation? - thats what satellite used

anonymous · Answer

if you mean "hard to see" refresh your browser.  maybe the latex is hidden

anonymous · Answer

if you mean you don't understand how i got 2x+2yy'=0
then let me know and i will explain
or jimmyrep will

anonymous · Answer

I don't an idea about implicit differentiation... because the only that my teacher taught is the directed distance formula, distance formula, completing the square, etc. our subject is analytic ge0m.

anonymous · Answer

ok fine we do this the hard way no problem

anonymous · Answer

your equation is 
$$x^2+y^2+2$$ a circle with center at (0,2) and radius 2

anonymous · Answer

hold on i am having some problem  not using calculus.  let's call for help

anonymous · Answer

correction it is $$x^{2}+y ^{2}=2 or x^{2}+y ^{2}-2=0$$