I need help with this question as soon as possible.
Find the vertices of the hyperbola with equation: (x-1)^2 / 4 - (y+2)^2 / 9 = 1

Question

I need help with this question as soon as possible.
Find the vertices of the hyperbola with equation:  (x-1)^2 / 4 - (y+2)^2 / 9 = 1

anonymous · Answer

(x,y)=(1,-2)

anonymous · Answer

Thank you :)

amistre64 · Answer

the equation gives you all the needed clues.

-(-1,2) is the center:  (1,-2)

the "x" part is positive so it rides along parallel to the x axis; meaning we adjust the "x" part from the center

and 4 is the under side of our "x" part so sqrt it to find the distance between vertexes"  sqrt(4) = 2

from center we go 1 to the left and 1 to the right (1+1 = 2)

(1+1,-2)  and  (1-1,-2)
   (2,-2)             (0,-2)

let me wolfram to dbl chk it tho

amistre64 · Answer

i was a bit off in my remembering; sqrt(4) = 2 then adjust left and right from center by "2" ....

amistre64 · Answer

(1+2,-2)  and  (1-2,-2)
  (3,-2)             (-1,-2)

we could make it simpler by lifting the equation to the x axis .. but thats for another time i spose

amistre64 · Answer

http://www.wolframalpha.com/input/?i=%28x-1%29^2+%2F+4+-+%28y%2B2%29^2+%2F+9+%3D+1