Question

This exercise deals with logarithmic scale.

If one earthquake is 20 times as intense as another, how much larger is its magnitude on the Richter scale?

Answer 1

Not familiar, some formula stuff here

http://en.wikipedia.org/wiki/Moment_magnitude_scale

Answer 2

we need richter scale formula for this one

Answer 3

let me find it

Answer 4

actually we probably don't. it is logarithmic scale, so answer is
\[\log(20)\]

Answer 5

It's on the link I gave, I thought...

Answer 6

i think the answer is about 3

Answer 7

i think its supposed to be 1.3

Answer 8

m=log I/s

Answer 9

where I is intensity and s is standard earthquake

Answer 10

m is magnitude

Answer 11

if intensity is of the first one is I then the richter scale is something like
\[\log(I)\]
then 20 times as intense gives
\[\log(20I)=\log(20)+\log(I)\] and
\[\log(20)=2.99...\] so i think it is about 3 more

Answer 12

are you sure of the answer 1.3 because i do not get that. the dividing by s part is not important. it is just a logarithmic scale

Answer 13

ya the professor says we should get log 20 = 1.3

Answer 14

oooooooooooooooooh because si am a moron

Answer 15

i was using the natural log and not the common log.

Answer 16

it is
\[\log(20)\] as i said, but
\[\log(20)=1.3...\]

Answer 17

ah i see

Answer 18

that is correct. i had the wrong log in my calculator.

Answer 19

sorry for the confustion

Answer 20

thanks for clearing that up