Question

rationalize the denominator √3/(√17) +3

Answer 1

Is it this? \(\large \frac{\sqrt{3}}{\sqrt{17} + 3}\)

Answer 2

yeah the 3 isnt under the square root.

Answer 3

multiply with sqr17-3 up and down

sqr3(sqr17-3)/8=sqr51-3sqr3

Answer 4

oh, then no.

Answer 5

it isn't? :/

Answer 6

Just put the two numbers over a common denominator, then add them, then rationalize the denominator.

Answer 7

what two numbers?

Answer 8

\(\frac{\sqrt{3}}{\sqrt{17}}\) and 3. The two numbers you're adding. They need to have a common denominator in order to add them.

Answer 9

there is no common denominator.

Answer 10

Sure there is. The LCD of 1 and sqrt(17) is sqrt(17)

Answer 11

thr is

Answer 12

im confused...

Answer 13

\[3 = \frac{3}{1} = \frac{3}{1} \cdot 1 = \frac{3}{1} \cdot \frac{\sqrt{17}}{\sqrt{17}} = \frac{3\sqrt{17}}{\sqrt{17}}\]

Answer 14

So then you can add it

Answer 15

so it would be 3√20 / √17 ?

Answer 16

No, you cannot add sqrts.

Answer 17

\[\sqrt{3} + 3\sqrt{17}\] cannot be futher combined.

Answer 18

ok

Answer 19

i am wiling to bet that this is the question\[\large \frac{\sqrt{3}}{\sqrt{17} + 3}\]

Answer 20

I thought so, but he said no.

Answer 21

because of the instructions that that "rationalize the denominator"

Answer 22

actually i think he said
yeah the 3 isnt under the square root.

Answer 23

oh, crud.

Answer 24

yeah, the three isnt under the square root.

Answer 25

\[\large \frac{3}{\sqrt{17} + 3}\]

Answer 26

I thought he said it wasn't under the fraction.

Answer 27

In that case, ignore what I said. You just want to multiply top and bottom by the conjugate of sqrt(17) + 3

Answer 28

@xxcrash do you see the correct question anywhere here?

Answer 29

no i dont understand how to do it

Answer 30

wouldnt the answer be √51 over 20? because 3(17) is 51? and then leave 3 on the bottom and add it to 17?

Answer 31

\[\frac{3}{\sqrt{17}+3}\times \frac{\sqrt{17}-3}{\sqrt{17}-3}\]
\[\frac{3(\sqrt{17}-3)}{\sqrt{17}\times \sqrt{17}-9}\]
\[\frac{3(\sqrt{17}-3)}{17-9}\]
\[\frac{3(\sqrt{17}-3)}{8}\]

Answer 32

the 3 on top is under a √ too...

Answer 33

then just rewrite exactly what i wrote, replacing the 3 by a root 3

Answer 34

but then wouldnt u multiply √3 by √17 ?

Answer 35

no

Answer 36

why ?

Answer 37

there is nothing in that expression that indicates for you to multiply
\[\sqrt{3}\times \sqrt{17}\]

Answer 38

ok

Answer 39

lets go slow and be clear.
first of all, is this what you started with
\[ \frac{\sqrt{3}}{\sqrt{17} + 3}\]

Answer 40

yeah